Question

Minimum excitation potential of Bohrs first orbit in hydrogen atom is:

• A. 3.6 V
• B. 10.2 V
• C. 13.6V
• D. 3.4V

Answer 1

Answer: (B)

10.2 V

Answer 2

From the relation $\Delta E=13.6\,eV-\frac{13.6\,eV}{{{n}^{2}}}$ $=13.6\,eV-\frac{13.6\,eV}{{{(2)}^{2}}}=10.2\,eV$ Therefore, excitation potential $=\frac{10.2}{e}eV=10.2\,V$