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Question: Minimum area of the triangle formed by any tangent to the ellipse x<sup>2</sup>/a<sup>2</sup> + y<su...

Minimum area of the triangle formed by any tangent to the ellipse x2/a2 + y2/b2 = 1 with coordinates axes is –

A

(a2+b2)2\frac{\left( a^{2} + b^{2} \right)}{2}

B

(a+b)22\frac{(a + b)^{2}}{2}

C

ab

D

(ab)22\frac{(a–b)^{2}}{2}

Answer

ab

Explanation

Solution

equation of tangent at (a cos q, b sin q)

= 1

area A = 12\frac{1}{2} (a sec q) (b cosec q)

A = absin2θ\frac{ab}{\sin 2\theta}

minimum = ab (Q (sin 2q) maximum = 1)