Question
Question: Metallic spheres of radii 6 cm, 8 cm and 10 cm, respectively, are melted to form a single solid sphe...
Metallic spheres of radii 6 cm, 8 cm and 10 cm, respectively, are melted to form a single solid sphere. Find the radius of the resulting sphere.
Solution
Hint: Volume of the 3 spheres when melted to form a single sphere will be equal. Equate the sum of volume of the 3 spheres with the volume of the new sphere to find the radius of the new sphere.
Three metallic spheres of radii 6 cm, 8 cm and 10 cm are to be melted and formed into a single sphere. Let the radius of the new sphere be ‘r’.
Let the radius of the three metallic spheres be r1, r2 and r3.
So we have, r1=6,r2=8,r3=10
When the three spheres are melted and formed into a single sphere, their volumes will remain the same. So, we can write it as,
(Volume of sphere 1 + Volume of sphere 2 + Volume of sphere 3)=Volume of the new sphere ..(1)
Volume of sphere 1= 34πr13
=34×π×(6)3 =3864πcm3
Volume of sphere 2= 34πr23
=34×π×(8)3 =32048πcm3
Volume of sphere 3= 34πr33
=34×π×(10)3 =34000πcm3
So as per equation (1), we need to add all the three volumes and equate it to the volume of the new sphere with radius ‘r’
Volume of new sphere= 3864π+32048π+34000π
=3π(864+2048+4000) =36912π =2304πcm3
Volume of new sphere= 34πr3
So, by equating both we get,
34πr3=2304π r3=46912 r3=1728
Expressing in terms of exponents where the exponent needs to be 3, we get
r3=123
When exponents are the same, the bases are equal.
r=12 cm
Hence the radius of the new sphere formed is 12 cm.
Note: In these types of problems, it is better to keep π till the end because it will be easier to calculate and in the end it might get cancelled. This also avoids the possibility of calculation errors.