Question

Melting point of $D_2O$ is higher than $H_2O$ because

• A. $D_2O$ shows stronger H-bonding than $H_2O$
• B. chemical reactions of $D_2O$ are slower than $H_2O$
• C. $D^+$ reacts slowly than $H^+$
• D. bond energy of O-D bond is higher than O-H bond.

Answer 1

Answer: (A)

$D_2O$ shows stronger H-bonding than $H_2O$

Answer 2

$D_2O$ shows stronger H-bonding than $H_2O$ and thus shows higher m.p. and b.p.