Question
Question: \(\cos \left[ \cos ^ { - 1 } \left( \frac { - 1 } { 7 } \right) + \sin ^ { - 1 } \left( \frac { - 1 ...
cos[cos−1(7−1)+sin−1(7−1)]=
A
−1/3
B
0
C
1/3
D
Answer
0
Explanation
Solution
cos{cos−1(7−1)+sin−1(7−1)}=cos2π=0 .
cos[cos−1(7−1)+sin−1(7−1)]=
−1/3
0
1/3
0
cos{cos−1(7−1)+sin−1(7−1)}=cos2π=0 .