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Question

Question: \(\sin \left\{ \sin ^ { - 1 } \frac { 1 } { 2 } + \cos ^ { - 1 } \frac { 1 } { 2 } \right\} =\)...

sin⁡{sin⁡−112+cos⁡−112}=\sin \left\{ \sin ^ { - 1 } \frac { 1 } { 2 } + \cos ^ { - 1 } \frac { 1 } { 2 } \right\} =

A

0

B

–1

C

2

D

1

Answer

1

Explanation

Solution

sin⁡(sin⁡−112+cos⁡−112)=sin⁡π2=1\sin \left( \sin ^ { - 1 } \frac { 1 } { 2 } + \cos ^ { - 1 } \frac { 1 } { 2 } \right) = \sin \frac { \pi } { 2 } = 1 .