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Question

Question: \(\tan \left( 90 ^ { \circ } - \cot ^ { - 1 } \frac { 1 } { 3 } \right) =\)...

tan⁡(90∘−cot⁡−113)=\tan \left( 90 ^ { \circ } - \cot ^ { - 1 } \frac { 1 } { 3 } \right) =

A

3

B

23\frac { 2 } { 3 }

C

13\frac { 1 } { 3 }

D

110\frac { 1 } { \sqrt { 10 } }

Answer

13\frac { 1 } { 3 }

Explanation

Solution

tan⁡(90∘−cot⁡−113)=cot⁡⋅cot⁡−113=13\tan \left( 90 ^ { \circ } - \cot ^ { - 1 } \frac { 1 } { 3 } \right) = \cot \cdot \cot ^ { - 1 } \frac { 1 } { 3 } = \frac { 1 } { 3 }.