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Question

Question: \(\int _ { 0 } ^ { \pi / 3 } \cos 3 x d x =\)...

0π/3cos3xdx=\int _ { 0 } ^ { \pi / 3 } \cos 3 x d x =

A

π\pi

B

0

C

π2\frac { \pi } { 2 }

D

π4\frac { \pi } { 4 }

Answer

0

Explanation

Solution

Required value is [sin3x3]0π/3=0\left[ \frac { \sin 3 x } { 3 } \right] _ { 0 } ^ { \pi / 3 } = 0.