QuestionReportQuestion: \(\int _ { 0 } ^ { \pi / 3 } \cos 3 x d x =\)...∫0π/3cos3xdx=\int _ { 0 } ^ { \pi / 3 } \cos 3 x d x =∫0π/3cos3xdx=Aπ\piπB0Cπ2\frac { \pi } { 2 }2πDπ4\frac { \pi } { 4 }4πAnswer0ExplanationSolutionRequired value is [sin3x3]0π/3=0\left[ \frac { \sin 3 x } { 3 } \right] _ { 0 } ^ { \pi / 3 } = 0[3sin3x]0π/3=0.