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Question

Question: \(\int _ { 0 } ^ { \pi } | \cos x | d x =\)...

∫0π∣cos⁡x∣dx=\int _ { 0 } ^ { \pi } | \cos x | d x =

A

π\pi

B

0

C

2

D

1

Answer

2

Explanation

Solution

∫0π∣cos⁡x∣dx=2∫0π/2∣cos⁡x∣dx=2[sin⁡x]0π/2=2\int _ { 0 } ^ { \pi } | \cos x | d x = 2 \int _ { 0 } ^ { \pi / 2 } | \cos x | d x = 2 [ \sin x ] _ { 0 } ^ { \pi / 2 } = 2 .