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Question

Question: \(\int _ { - 3 } ^ { 3 } \frac { x ^ { 2 } \sin 2 x } { x ^ { 2 } + 1 } d x =\)...

33x2sin2xx2+1dx=\int _ { - 3 } ^ { 3 } \frac { x ^ { 2 } \sin 2 x } { x ^ { 2 } + 1 } d x =

A

0

B

1

C

2loge32 \log _ { e } 3

D

None of these

Answer

0

Explanation

Solution

Obviously the function x2sin2xx2+1\frac { x ^ { 2 } \sin 2 x } { x ^ { 2 } + 1 }is odd, so

33x2sin2xx2+1dx=0\int _ { - 3 } ^ { 3 } \frac { x ^ { 2 } \sin 2 x } { x ^ { 2 } + 1 } d x = 0.