QuestionReportQuestion: \(\int _ { 0 } ^ { \pi } \cos ^ { 3 } x d x =\)...∫0πcos3xdx=\int _ { 0 } ^ { \pi } \cos ^ { 3 } x d x =∫0πcos3xdx=A−1- 1−1B0C1Dπ\piπAnswer0ExplanationSolution, {∵cos3(π−x)=−cos3x}\left\{ \because \cos ^ { 3 } ( \pi - x ) = - \cos ^ { 3 } x \right\}{∵cos3(π−x)=−cos3x}.