Question

$\lim _ { x \rightarrow 0 }$ $\frac{3^{2x} - 2^{3x}}{x}$is equal to-

• A. log $\frac{9}{8}$
• B. log $\frac { 8 } { 9 }$
• C. –log $2^{10}$
• D. log 72

Answer 1

Answer: (A)

log $\frac{9}{8}$

Answer 2

$\lim _ { x \rightarrow 0 }$=$\lim _ { x \rightarrow 0 }$

= 2 log 3 – 3 log 2 = log 9 – log 8 = log $\left( \frac { 9 } { 8 } \right)$