Question
Question: \...
n+1nasin2(n!), (0 < a < 1) =
A
1
B
+
C
0
D
None of these
Answer
0
Explanation
Solution
limn→α (1+n1)na−1+sin2(n!)= 1(α)a−1.[0,1]= 0 × [0, 1]
(Q 0 < a < 1 Ž aa–1 Ž a –ve = 0) = 0