Question

$\lim _ { x \rightarrow \infty }$ $\left( \frac{x + 6}{x + 1} \right)^{x + 4}$ =

• A. e
• B. e⁴
• C. e⁵
• D. e⁶

Answer 1

Answer: (C)

e⁵

Answer 2

$\lim_{x \rightarrow \infty}$ $\left( \frac{x + 6}{x + 1} \right)^{x + 4}$ = 1^ form

Ž $\mathrm { e } ^ { \lim _ { \mathrm { x } \rightarrow \infty } ( \mathrm { x } + 4 ) \left[ \frac { \mathrm { x } + 6 } { \mathrm { x } + 1 } - 1 \right] }$ =

= $e^{\lim_{x \rightarrow \infty}\frac{5x + 20}{x + 1}}$ = e⁵