Solveeit Logo
Login

Question

Question: \(0.195\)m what is the value of \(K _ { H }\)...

0.1950.195m what is the value of KHK _ { H }

A

B

C

192 bar

D

282 bar

Answer

282 bar

Explanation

Solution

No. of moles of H2 S=0.195\mathrm { H } _ { 2 } \mathrm {~S} = 0.195

No. of moles of H2O=100018=55.55 mol\mathrm { H } _ { 2 } \mathrm { O } = \frac { 1000 } { 18 } = 55.55 \mathrm {~mol}

Mole fraction of H2 S=0.1950.195+55.55=0.0035\mathrm { H } _ { 2 } \mathrm {~S} = \frac { 0.195 } { 0.195 + 55.55 } = 0.0035

Pressure at STP = 0.987 bar

According to Henry’s law p=kHx\mathrm { p } = \mathrm { k } _ { \mathrm { H } } \mathrm { x }

Or KH=pH2 SXH2 S=0.9870.0035=282bar\mathrm { K } _ { \mathrm { H } } = \frac { \mathrm { p } _ { \mathrm { H } _ { 2 } \mathrm {~S} } } { \mathrm { X } _ { \mathrm { H } _ { 2 } \mathrm {~S} } } = \frac { 0.987 } { 0.0035 } = 282 \mathrm { bar }