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Question: \(\xrightarrow [ \mathrm { H } ^ { + } ] { \mathrm { HCN } }\)C<sub>7</sub>H<sub>11</sub>ON \(\xrigh...

H+HCN\xrightarrow [ \mathrm { H } ^ { + } ] { \mathrm { HCN } }C7H11ON  DIBAL-H \xrightarrow { \text { DIBAL-H } } Q,

P and Q are –

A

NaBH4 ,

B

Ni–H2, in ethanol,

C

LiAlH4,

D

Pd–H2, in quinoline at room temp.

Answer

Pd–H2, in quinoline at room temp.

Explanation

Solution

H+HCN\xrightarrow [ \mathrm { H } ^ { + } ] { \mathrm { HCN } }

(P)

 DIBAL-H \xrightarrow { \text { DIBAL-H } }

\ P is Pd–H2, in quinoline at room temp.,

Q is