Question

.

The reagent is.

• A. Na
• B. HCl and $\mathrm { H } _ { 2 } \mathrm { O }$
• C. KOH in $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH }$
• D. Zn

Answer 1

Answer: (C)

KOH in $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH }$

Answer 2

$\mathrm { R } - \mathrm { CH } _ { 2 } - \mathrm { CCl } _ { 2 } - \mathrm { R } \xrightarrow { \mathrm { KOH } + \mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH } }$

$\mathrm { R } - \mathrm { C } \equiv \mathrm { C } - \mathrm { R } + 2 \mathrm { HCl }$

This reaction is an example of dehydrohalogenation Hence, alcoholic KOH is used as a reagent.