Question

$\mathrm { H } _ { 3 } \mathrm { C } - \stackrel { \oplus } { \mathrm { C } } \mathrm { H } - \mathrm { CH } = \mathrm { CH } _ { 2 }$does not involve :

• A. s–p overlap
• B. s–s overlap
• C. pp–ppoverlap
• D. pp–dp overlap

Answer 1

Answer: (D)

pp–dp overlap

Answer 2

$\mathrm { H } _ { 3 } \mathrm { C } - \stackrel { \oplus } { \mathrm { C } } \mathrm { H } - \mathrm { CH } = \mathrm { CH } _ { 2 }$in this $\sigma$ -p orverlapping occurs due to Hyperconjugation and p $\pi$ –p $\pi$ overlap occur due to resonance.