Question

, number of geometrical isomers for the compound is -

• A. 20
• B. 16
• C. 4
• D. 8

Answer 1

Answer: (A)

20

Answer 2

No. of double bonds or n = odd i.e. = 5

So G.I. = 2^n–1 + 2p^–1 $\left[ \mathrm { P } = \frac { \mathrm { n } + 1 } { 2 } \right]$