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Question

Question: ![](https://cdn.pureessence.tech/canvas_80.png?top_left_x=1666&top_left_y=0&width=300&height=146) V...

VA – V­B is -

A

Zero

B

2V

C

3.5 V

D

4.5 V

Answer

4.5 V

Explanation

Solution

ENet = 62+6112+11\frac{\frac{6}{2} + \frac{6}{1}}{\frac{1}{2} + \frac{1}{1}}= 9×23\frac{9 \times 2}{3} = 6V, req = 2/3

I = 62+23=6×38=94\frac{6}{2 + \frac{2}{3}} = \frac{6 \times 3}{8} = \frac{9}{4}= 2.25

∴ VA–VB = IR = 2.25 × 2 = 4.5 Volts