Question

$62.5 \times 10 ^ { 18 }$ electrons per second are flowing through a wire of area of cross-section 0.1$m ^ { 2 }$, the value of current flowing will be

• A. 1 A
• B. 0.1 A
• C. 10 A
• D. 0.11 A

Answer 1

Answer: (C)

10 A

Answer 2

$i = \frac { n e } { t } = \frac { 62.5 \times 10 ^ { 18 } \times 1.6 \times 10 ^ { - 19 } } { 1 } = 10$ ampere