Mean kinetic energy per degree of freedom of gas molecules i... | PHYSICS - KINETIC THEORY OF AN IDEAL GAS | SolveeIt | Solveeit

Today, August 19

Question

Mean kinetic energy per degree of freedom of gas molecules is-

A

$\frac{3}{2}$ kT

B

kT

C

$\frac{1}{2}$ kT

D

$\frac{3}{2}$ RT

Answer

$\frac{1}{2}$ kT

Explanation

Solution

According to law of equipartition of energy, kinetic energy per degree of freedom of a gas molecule is $\frac{1}{2}$ kT.