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Question

Physics Question on Electromagnetic waves

Maxwell?? modified form of Ampere?? circuital law is

A

∮sB⃗.ds⃗=0\oint_s \vec{B} . \vec{ds} = 0

B

∮sB⃗.dl⃗=μ0I\oint_s \vec{B} . \vec{dl} = \mu_0 I

C

∮sB⃗.dl⃗=μ0I+1εodqdt\oint_s \vec{B} . \vec{dl} = \mu_0 I + \frac{1}{\varepsilon_o} \frac{dq}{dt}

D

∮sB⃗.dl⃗=μ0I+μ0εodϕEdt\oint_{s} \vec{B} . \vec{dl} = \mu_{0} I + \mu_{0} \varepsilon_{o} \frac{d \phi_{E}}{d t}

Answer

∮sB⃗.dl⃗=μ0I+μ0εodϕEdt\oint_{s} \vec{B} . \vec{dl} = \mu_{0} I + \mu_{0} \varepsilon_{o} \frac{d \phi_{E}}{d t}

Explanation

Solution

Answer (d) ∮sB⃗.dl⃗=μ0I+μ0εodϕEdt\oint_{s} \vec{B} . \vec{dl} = \mu_{0} I + \mu_{0} \varepsilon_{o} \frac{d \phi_{E}}{d t}