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Question

Question: Maximum kinetic energy of the positive ion in the cyclotron is...

Maximum kinetic energy of the positive ion in the cyclotron is

A

(a) q2Br02m\frac { q ^ { 2 } B r _ { 0 } } { 2 m }

A

(b) qB2ro2m\frac { q B ^ { 2 } r _ { o } } { 2 m }

A

(c) q2B2r022m\frac { q ^ { 2 } B ^ { 2 } r _ { 0 } ^ { 2 } } { 2 m }

A

(d) qBr02m2\frac { q B r _ { 0 } } { 2 m ^ { 2 } }

Explanation

Solution

(c)

Sol. Kmax=12mv2K _ { \max } = \frac { 1 } { 2 } m v ^ { 2 } and r0=mvqBr _ { 0 } = \frac { m v } { q B }