Question

Maximum distance of any point on the circle }

(x –7)² + (y –2 $\sqrt{30}$)² = 16 from the centre of the ellipse

25x² + 16y² = 400 is

• A. $\frac{1 - \sqrt{3}}{2}$
• B. $\frac{3}{2}$
• C. 3
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

Q centre of ellipse (0, 0) and centre of circle is

(7, 2$\sqrt{30}$) and radius is 4

\ maximum distance of any point on the circle from the centre of the ellipse

= $\sqrt{(7 - 0)^{2} + (2\sqrt{30} - 0)^{2}}$+ 4 = 17