Question
Mathematics Question on types of differential equations
max0≤x≤π x−2sin.xcos+31sin3x=
A
6π+2−33
B
65π+2−33
C
π
D
0
Answer
65π+2−33
Explanation
Solution
The correct option is(B): 65π+2−33
max0≤x≤π x−2sin.xcos+31sin3x=
6π+2−33
65π+2−33
π
0
65π+2−33
The correct option is(B): 65π+2−33