Question

Matte contains;
A.$C{{u}_{2}}S,FeS$ and silica
B.$C{{u}_{2}}S,FeO$ and silica
C.$C{{u}_{2}}S,CuO$ and silica
D.$C{{u}_{2}}S,C{{u}_{2}}O$ and silica

Answer 1

Matte is the mixture of both copper and sulphur. Copper matte is a compound of copper and the process matte is defined as the extraction of the metal before the final reduction. Copper matte is an alloy of a mixture of two or more compounds.

Complete step-by-step answer: Metallurgy is a branch that deals with the physical and chemical behaviour of the metallic elements. It includes science of metals and technology.
Copper matte is defined as a mixture of compounds of copper sulphide and iron sulphide. Matte is a phase before the final reduction. In this process, we introduce ore into a blast furnace after mixing with coke and silica. Conversion of ferrous oxide to ferrous silicate takes place after air is blasted in the furnace. The slag appeared on the copper matte.
Let us see the reaction-
$2FeS+3{{O}_{2}}\xrightarrow{\Delta }2FeO+2S{{O}_{2}}$
$FeO+\dfrac{1}{4}{{O}_{2}}\to Fe{{O}_{1.5}}$
$FeO+Si{{O}_{2}}\to FeSi{{O}_{3}}$
$FeSi{{O}_{3}}$( ferrosilite) is a slag.
After the above explanation, we got to know that matte is a mixture of copper sulphide, iron sulphide and silica.

Additional information: Metallurgy is a process of extraction of metals in pure form. The metallurgy is classified into crushing and grinding, the concentration of ore, hydrolytic method, magnetic separation, froth floatation, roasting and calcination.

Hence option A. is correct.

Note: In this question we concluded that when a hot blast of air is blown through a matte present in a silica lined converter then conversion of ferrous sulphide to ferrous oxide takes place. After that ferrous oxide combines with silicon dioxide that result in the formation of ferrosilite