Question

$\mathrm{VO}+\mathrm{Fe}_{2} \mathrm{O}_{3} \rightarrow \mathrm{FeO}+\mathrm{V}_{2} \mathrm{O}_{5}$

Answer 1

The balanced chemical equation is:

$2\mathrm{VO}+3\mathrm{Fe}_{2} \mathrm{O}_{3} \rightarrow 6\mathrm{FeO}+\mathrm{V}_{2} \mathrm{O}_{5}$

Answer 2

The given unbalanced equation $\mathrm{VO}+\mathrm{Fe}_{2} \mathrm{O}_{3} \rightarrow \mathrm{FeO}+\mathrm{V}_{2} \mathrm{O}_{5}$ is balanced by ensuring the number of atoms of each element is equal on both the reactant and product sides. By assigning stoichiometric coefficients and solving the resulting system of linear equations for the atoms of V, Fe, and O, the coefficients are found to be 2 for VO, 3 for $\mathrm{Fe}_{2} \mathrm{O}_{3}$, 6 for FeO, and 1 for $\mathrm{V}_{2} \mathrm{O}_{5}$.