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Question

Question: \[\mathbf{i}.(\mathbf{j} \times \mathbf{k}) + \mathbf{j}.(\mathbf{k} \times \mathbf{i}) + \mathbf{k}...

i.(j×k)+j.(k×i)+k.(i×j)=\mathbf{i}.(\mathbf{j} \times \mathbf{k}) + \mathbf{j}.(\mathbf{k} \times \mathbf{i}) + \mathbf{k}.(\mathbf{i} \times \mathbf{j}) =

A

1

B

3

C

– 3

D

0

Answer

3

Explanation

Solution

i.(j×k)+j.(k×i)+k.(i×j)\mathbf{i}.(\mathbf{j} \times \mathbf{k}) + \mathbf{j}.(\mathbf{k} \times \mathbf{i}) + \mathbf{k}.(\mathbf{i} \times \mathbf{j}) =i.i+j.j+k.k=3.\mathbf{i}.\mathbf{i} + \mathbf{j}.\mathbf{j} + \mathbf{k}.\mathbf{k} = 3.