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Question

Question: \((\mathbf{b} \times \mathbf{c}) \times (\mathbf{c} \times \mathbf{a}) =\)...

(b×c)×(c×a)=(\mathbf{b} \times \mathbf{c}) \times (\mathbf{c} \times \mathbf{a}) =

A

[b c a] a

B

[c a b] b

C

[a b c] c

D

[a c b] b

Answer

∗∗abc∗∗**a b c** c

Explanation

Solution

(b×c.a)c−(b×c.c)a=[bca]c−0=[abc]c(\mathbf{b} \times \mathbf{c}.\mathbf{a})\mathbf{c} - (\mathbf{b} \times \mathbf{c}.\mathbf{c})\mathbf{a} = \lbrack\mathbf{bca}\rbrack\mathbf{c} - \mathbf{0} = \lbrack\mathbf{abc}\rbrack\mathbf{c}.