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Question

Question: \[\mathbf{a}.(\mathbf{a} \times \mathbf{b}) =\]...

a.(a×b)=\mathbf{a}.(\mathbf{a} \times \mathbf{b}) =

A

b . b

B

a2ba^{2}b

C

0

D

a2+aba^{2} + ab

Answer

0

Explanation

Solution

Since a×b\mathbf{a} \times \mathbf{b} is perpendicular to a\mathbf{a} and b\mathbf{b} both, therefore a.(a×b)=0.\mathbf{a}.(\mathbf{a} \times \mathbf{b}) = 0.

((\becauseScalar product of two perpendicular vector is zero)