Question

Match the rate expressions in LIST-I for the decomposition of X with the corresponding profiles provided in

LIST-II. Xs and k are constants having appropriate units.LIST I	LIST II
I	rate =$\frac{k[X]}{Xs+[X]}$
under all possible initial concentration of****X	P
II	rate =$\frac{k[X]}{Xs+[X]}$
where initial concentration of X are much less than _X s_​
Q
III	rate =$\frac{k[X]}{Xs+[X]}$
where initial concentration of X are much higher than _X s_​
R
IV	rate =$\frac{k[X]^2}{Xs+[X]}$,where initial concentration of X is much higher than Xs​
S
	T

• A. I → P; II → Q; III → S; IV → T
• B. I → R; II → S; III → S; IV → T
• C. I → P; II → Q; III → Q; IV → R
• D. I → R; II → S; III → Q; IV → R

Answer 1

Answer: (A)

I → P; II → Q; III → S; IV → T

Answer 2

$(I)$ Rate=$\frac{k[X]}{Xs+[X]}$
$\text{If} [x]→∞⇒ rate →k⇒ order =0$
$⇒(I)−(R),(P)$

$(II)$ $[x]<<x _s ​ ⇒ rate = ​\frac{k[x]}{x_s} ​ ⇒ order =1$
$⇒ (II) −(Q), (T)$

$(III) [x]>>x _s ​ ⇒ rate =k⇒ order =0$
$⇒(III)−(P),(S)$

$(IV)$ rate =$\frac{k[X]^2}{Xs+[X]}$
$[x]>>x _s ​ ⇒ rate =k[x]$
$⇒(IV)−(Q),(T)$