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Question: Match the physical properties of Column-I with their values in Column-II. Column-I| Column-II...

Match the physical properties of Column-I with their values in Column-II.

Column-IColumn-II
(a) SATP(p) 1 bar/1 atm
(b) Temperature in STP(q) 99.6oC99.6^{ o }{ C }
(c) Pressure in NTP(r) 273.15 K
(d) Standard boiling point of water(s) 298.15 K

SATP: Standard Ambient temperature and Pressure
STP: Standard Temperature and Pressure
NTP: Normal Temperature and pressure

Explanation

Solution

Hint: Standard references are established since the temperature and pressure conditions vary from place to place. Therefore we use STP, NTP, SATP and other standards as reference. Out of all these, the SATP standard is the most convenient.

Complete step-by-step answer:
Let us understand SATP, STP and NTP conditions and why we need them.
SATP: It refers to Standard Ambient temperature and Pressure. It is defined by the International Union of Pure and Applied Chemistry (IUPAC) and is used as a reference standard condition. Since the standard ambient temperature is 25oC 25^{ o }{ C } (298.15 K) therefore it is easier to take SATP as the reference standard condition since achieving 25oC 25^{ o }{ C } (298.15 K) is more convenient than 0oC0^{ o }{ C } (273.15 K)which is used in STP conditions. The molar volume of an ideal gas at SATP conditions is 24.79 dm3mol1{ dm }^{ 3 }{ mol }^{ -1 }.
STP: It refers to Standard Temperature and Pressure. It refers to air at a 0oC0^{ o }{ C } (273.15 K) temperature and 1 bar pressure. The molar volume of an ideal gas at STP conditions is 22.4 L. Earlier the IUPAC defined STP as 0oC0^{ o }{ C } (273.15 K) temperature and 1 atm pressure which has been discontinued now.
NTP: It refers to Normal Temperature and pressure. It refers to air at a temperature of 20oC 20^{ o }{ C } (293.15 K) and a pressure of 1 atm. The molar volume of an ideal gas at NTP conditions is 24.05 L.
The standard boiling point of water is the temperature at which water boils at an external pressure of 1 bar. This temperature is equal to 99.6oC99.6^{ o }{ C }.
Keeping all the above points in mind, we can write the solution.
Hence the answer to the question is:

Column-IColumn-II
(a) SATP(s) 298.15 K
(b) Temperature in STP(r) 273.15 K
(c) Pressure in NTP(p) 1 bar/1 atm
(d) Standard boiling point of water(q) 99.6oC99.6^{ o }{ C }

Note: STP conditions are generally employed by scientists when the measurements involve a gas since the properties of the gas change dramatically with the change in temperature and pressure conditions. There is a slight difference between the updated definition of STP by IUPAC and Imperial and USA system of units. The former defines STP as 0oC0^{ o }{ C } (273.15 K) temperature and 1 bar pressure while the latter defines it as a temperature of 15.6oC15.6^{ o }{ C } and a pressure of 1 atm.