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Question

Chemistry Question on Haloalkanes and Haloarenes

Match the following lists:

A

A-4 B-3 C-2 D-1

B

A-3 B-4 C-2 D-5

C

A-2 B-5 C-3 D-4

D

A-5 B-2 C-3 D-4

Answer

A-4 B-3 C-2 D-1

Explanation

Solution

Wurtz reaction: Alkyl halide when heated with metallic sodium and zinc powder in ether gives alkane by joining two alkyl groups. 2RX+2NaetherR.R+2NaX2RX+2Na\xrightarrow{\text{ether}}R.R+2NaX Williamson synthesis: It is the laboratory preparation of ether. RONaSod.alkoxide+XRAlkylΔROREther+NaX\underset{\text{Sod}\text{.alkoxide}}{\mathop{RONa}}\,+\underset{\text{Alkyl}}{\mathop{XR}}\,\xrightarrow{\Delta }\underset{\text{Ether}}{\mathop{ROR}}\,+NaX Hell-Volhard-Zelinsky reaction: α\alpha - chloro or α\alpha - bromo acids are usually prepared by first converting the acid into its chloride and bromide and then carrying out chlorination or bromination. Thus is called HV Z reaction. So, is for α\alpha - halogenation. RCH2COOHAddP + Br2RCH2CO.BrAcidbromide\underset{\text{Add}}{\mathop{RC{{H}_{2}}COOH}}\,\xrightarrow{\text{P + B}{{\text{r}}_{\text{2}}}}\underset{\text{Acid}\,\text{bromide}}{\mathop{RC{{H}_{2}}CO.Br}}\,
Aldol condensation: When aldehydes and ketones having α\alpha - hydogen atoms are treated with alkali they undergo self-addition between two molecules to form a β\beta - hydroxy aldehyde or ketone (known as aldol). This addition is usually followed by elimination of a water molecule resulting in overall condensation reaction. CH3CHO+CH3CHOOHCH3CHOHCH2CHOβhydroxybutyraldehyde (Aldol)C{{H}_{3}}CHO+C{{H}_{3}}CHO\xrightarrow{O{{H}^{-}}}\underset{\begin{smallmatrix} \beta -\text{hydroxy}\,\text{butyraldehyde} \\\ \text{(Aldol)} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}CHO}}\, Molasses: Ethyl alcohol is obtained from molasses. It is obtained as a byproduct of sugarindustry.