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Question: Match the compounds given in column I with oxidation states of carbon given in column II and mark th...

Match the compounds given in column I with oxidation states of carbon given in column II and mark the appropriate choice.

Column IColumn II
(A)C6H12O6C_{6}H_{12}O_{6}(i)+3
(B)CHCl3CHCl_{3}(ii)-3
(C)CH3CH3CH_{3}CH_{3}(iii)+2
(D)(COOH)2(COOH)_{2}(iv)0
A

(A) \rightarrow (iv), (B) \rightarrow (iii), (C) \rightarrow (ii), (D) \rightarrow (i)

B

(A) \rightarrow (i), (B) \rightarrow (ii), (C) \rightarrow (iii), (D) \rightarrow (iv)

C

(A) \rightarrow (ii),(B) \rightarrow (iii),(C) \rightarrow (iv), (D) \rightarrow (i)

D

(A) \rightarrow (iii), (B) \rightarrow (ii), (C) \rightarrow (i), (D) \rightarrow (iv)

Answer

(A) \rightarrow (iv), (B) \rightarrow (iii), (C) \rightarrow (ii), (D) \rightarrow (i)

Explanation

Solution

: C6H12O6:6x+12+(12)=0x=0C_{6}H_{12}O_{6}:6x + 12 + ( - 12) = 0 \Rightarrow x = 0

CHCl3:x+1+(3)=0x=+2CHCl_{3}:x + 1 + ( - 3) = 0 \Rightarrow x = + 2

CH3CH3;x+3+x+3=0x=3CH_{3}CH_{3};x + 3 + x + 3 = 0 \Rightarrow x = - 3

(COOH)2:x+x+(4×2)+(+2)=0x=+3(COOH)_{2}:x + x + ( - 4 \times 2) + ( + 2) = 0 \Rightarrow x = + 3