Question

Match the column Iwith column II and mark the appropriate choice.

	Column I (Compound)		Column II (Oxidation state of Fe)
(A)	K3[Fe(OH)6]	(i)	+8/3
(B)	K2[FeO4]	(ii)	+2
(C)	FeSO4(NH4)2SO46H2O	(iii)	+3
(D)	Fe3O4	(iv)	+6

• A. (A) $\rightarrow$ (iii), (B) $\rightarrow$ (i), (C) $\rightarrow$ (ii), (D) $\rightarrow$ (iv)
• B. (A) $\rightarrow$ (iii), (B) $\rightarrow$ (iv), (C) $\rightarrow$ (ii), (D) $\rightarrow$ (i)
• C. (A) $\rightarrow$ (i), (B) $\rightarrow$ (iii), (C) $\rightarrow$ (ii), (D) $\rightarrow$ (iv)
• D. (A) $\rightarrow$ (iv), (B) $\rightarrow$ (ii), (C) $\rightarrow$ (i), (D) $\rightarrow$ (iii)

Answer 1

Answer: (B)

(A) $\rightarrow$ (iii), (B) $\rightarrow$ (iv), (C) $\rightarrow$ (ii), (D) $\rightarrow$ (i)

Answer 2

: $K_{3}\lbrack Fe(OH)_{6}\rbrack \rightarrow + 3 + x - 6 = 0 \Rightarrow x = + 3$

$K_{2}\lbrack FeO_{4}\rbrack \rightarrow + 2 + x - 8 = 0 \Rightarrow x = + 6$

$FeSO_{4}(NH_{4})_{2}SO_{4}6H_{2}O$

In $FeSO_{4} \rightarrow x - 2 = 0 \Rightarrow x = + 2$

$Fe_{3}O_{4} = FeO + Fe_{2}O_{3} \rightarrow x - 2 + 2x - 6 = 0$

$\Rightarrow 3x = + 8 \Rightarrow x = + 8/3$