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Question: Match the column I with column II in which formula for estimation of an element is given and mark th...

Match the column I with column II in which formula for estimation of an element is given and mark the appropriate choice.

Column IColumn II
(A)

Estimation of

carbon

(i)$$\frac{80}{188} \times \frac{w_{1}}{W} \times 100$$
(B)

Estimation of

nitrogen

(ii)$$\frac{62}{222} \times \frac{w_{1}}{w} \times 100$$
(C)

Estimation of

bromine

(iii)$$\frac{32}{233} \times \frac{w_{1}}{w} \times 100$$
(D)

Estimation of

sulphur

(iv)$$\frac{28}{22400} \times \frac{V}{w} \times 100$$
(E)

Estimation of

phosphorus

(v)$$\frac{12}{44} \times \frac{w_{1}}{w} \times 100$$
A

(A) \rightarrow (v), (B) \rightarrow (ii), (C) \rightarrow (iv), (D) \rightarrow (i),

(E) \rightarrow (iii)

B

(A) \rightarrow (v), (B) \rightarrow (iv), (C) \rightarrow (i), (D) \rightarrow (iii),

(E) \rightarrow (ii)

C

(A) \rightarrow (v), (B) \rightarrow (iv), (C) \rightarrow (ii), (D) \rightarrow (i),

(E) \rightarrow (iii)

D

(A) \rightarrow (iv), (B) \rightarrow (iii), (C) \rightarrow (i), (D) \rightarrow (ii),

(E) \rightarrow (v)

Answer

(A) \rightarrow (v), (B) \rightarrow (iv), (C) \rightarrow (i), (D) \rightarrow (iii),

EE \rightarrow (ii)

Explanation

Solution

: % of C=1244×w1w×100C = \frac{12}{44} \times \frac{w_{1}}{w} \times 100

(w1w_{1} = weight of CO2,CO_{2}, w = weight of organic compound)

% of N=2822400×Vw×100N = \frac{28}{22400} \times \frac{V}{w} \times 100

(V = volume of N2N_{2} at STP, w = weight of organic comopound)

% of Br=80188×w1w×100Br = \frac{80}{188} \times \frac{w_{1}}{w} \times 100 (w1w_{1} = weight ofAgBr)

% of S=32233×w1w×100S = \frac{32}{233} \times \frac{w_{1}}{w} \times 100 (w1w_{1}= weight of BaSO4BaSO_{4})

% of P=62222×w1w×100P = \frac{62}{222} \times \frac{w_{1}}{w} \times 100 (w1w_{1} = weight of Mg2P2O7Mg_{2}P_{2}O_{7})