Question
Question: Match the column:...
Match the column:

A
A: a → p, b → r, c → q, d → q, r
B
B: a → p, b → r, c → q, d → p, q
C
C: a → p, b → r, c → q, d → p
D
D: a → r, b → p, c → q, d → p, r
Answer
A: a → p, b → r, c → q, d → q, r
Explanation
Solution
The problem asks us to match the given conditions related to magnetic properties with the type of magnetic materials.
Let's analyze each condition:
Understanding the terms:
- x (or χ): Represents magnetic susceptibility. It's a dimensionless quantity that describes how much a material will become magnetized in an applied magnetic field.
- μ: Represents magnetic permeability of the material. It's a measure of the ability of a material to support the formation of a magnetic field within itself.
- μ₀: Represents the permeability of free space (vacuum). Its value is 4π×10−7 T⋅m/A.
The relationship between magnetic permeability (μ) and magnetic susceptibility (χ) is given by: μ=μ0(1+χ)
Now, let's match the columns:
Column A Analysis:
-
(a) -1 ≤ x < 0:
- For diamagnetic materials, the magnetic susceptibility (χ) is small and negative. This range perfectly describes diamagnetic behavior.
- Therefore, (a) → (p) Diamagnetic.
-
(b) 0 < x < 1:
- For paramagnetic materials, the magnetic susceptibility (χ) is small and positive. This range indicates paramagnetic behavior.
- Therefore, (b) → (r) Paramagnetic.
-
(c) x >> 1:
- For ferromagnetic materials, the magnetic susceptibility (χ) is very large and positive (typically in the range of hundreds to hundreds of thousands). This condition signifies ferromagnetic behavior.
- Therefore, (c) → (q) Ferromagnetic.
-
(d) μ > μ₀:
- Using the relationship μ=μ0(1+χ): If μ>μ0, then μ0(1+χ)>μ0. Dividing by μ0 (which is positive), we get 1+χ>1. This simplifies to χ>0.
- Materials with positive susceptibility (χ > 0) include both paramagnetic materials (where χ is small and positive) and ferromagnetic materials (where χ is very large and positive).
- Therefore, (d) → (q) Ferromagnetic, (r) Paramagnetic.
Summary of Matches:
- (a) → (p)
- (b) → (r)
- (c) → (q)
- (d) → (q), (r)
Comparing this with the given options, Option A matches our derived solution.