Solveeit Logo

Question

Chemistry Question on Qualitative Analysis

Match List-I with the List-IIList-I
(Precipitating reagent and
conditions)| List-II
(Cation)
---|---
(A) NH4Cl+NH4OHNH_4Cl + NH_4OH| (I) Mn2+
(B) NH4OH+Na2CO3NH_4OH + Na_2CO_3| (II) Pb2+
(C) NH4OH+NH4Cl+H2SgasNH_4OH + NH_4Cl + H_2S gas| (III) Al3+
(D) dilute HCl| (IV) Sr2+
Choose the correct answer from the options given below:

A

A-IV, B-III, C-II, D-I

B

A-IV, B-III, C-I, D-II

C

A-III, B-IV, C-I, D-II

D

A-III, B-IV, C-II, D-I

Answer

A-III, B-IV, C-I, D-II

Explanation

Solution

The matching is based on the chemical properties and specific precipitation conditions for cations:
[A.] NH4_4Cl + NH4_4OH precipitates Al(OH)3_3, hence matches with III. Al3+^{3+}.
[B.] NH4_4OH + Na2_2CO3_3 precipitates SrCO3_3, hence matches with IV. Sr2+^{2+}.
[C.] NH4_4OH + NH4_4Cl + H2_2S gas precipitates PbS, hence matches with II. Pb2+^{2+}.
[D.] Dilute HCl precipitates MnCl2_2, hence matches with I. Mn2+^{2+}.
Thus, the correct order is:
AIII,BIV,CII,DI.A -- III, B -- IV, C -- II, D -- I.