Question
Chemistry Question on Qualitative Analysis
Match List-I with the List-IIList-I
(Precipitating reagent and
conditions)| List-II
(Cation)
---|---
(A) NH4Cl+NH4OH| (I) Mn2+
(B) NH4OH+Na2CO3| (II) Pb2+
(C) NH4OH+NH4Cl+H2Sgas| (III) Al3+
(D) dilute HCl| (IV) Sr2+
Choose the correct answer from the options given below:
A-IV, B-III, C-II, D-I
A-IV, B-III, C-I, D-II
A-III, B-IV, C-I, D-II
A-III, B-IV, C-II, D-I
A-III, B-IV, C-I, D-II
Solution
The matching is based on the chemical properties and specific precipitation conditions for cations:
[A.] NH4Cl + NH4OH precipitates Al(OH)3, hence matches with III. Al3+.
[B.] NH4OH + Na2CO3 precipitates SrCO3, hence matches with IV. Sr2+.
[C.] NH4OH + NH4Cl + H2S gas precipitates PbS, hence matches with II. Pb2+.
[D.] Dilute HCl precipitates MnCl2, hence matches with I. Mn2+.
Thus, the correct order is:
A−−III,B−−IV,C−−II,D−−I.