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Question

Chemistry Question on Molecular Orbital Theory

Match List-I with List -IIList - IList - II
(A) ψMO=ψAψBψ_{MO}=ψ_A-ψ_B(I) Dipole moment
(B) µ=Q×rµ=Q×r (II) Bonding molecular orbital
(C) NbNa2\frac{N_b-N_a}2(III) Anti-bonding molecular orbital
(D) ψMO=ψA+ψBψ_{MO}=ψ_A+ψ_B(IV) Bond order

Choose the correct answer from options given below:

A

A(II), B(I), C(IV), D(III)

B

A(III), B(IV), C(I), D(II)

C

A(III), B(I), C(IV), D(II)

D

A(III), B(IV), C(II), D(I)

Answer

A(III), B(I), C(IV), D(II)

Explanation

Solution

The correct answer is (C).
ψAψB=ψMOψ_A-ψ_B=ψ_{MO} is anti-bonding molecular orbital
µ=Q×rµ = Q×r ∼ is dipole moment
NbNa2\frac{N_b-N_a}2 = bond order
ψA+ψB=ψMOψ_A+ψ_B=ψ_{MO} is bonding molecular orbital.