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Chemistry Question on Planck’s quantum theory

Match List I with List IIList IList II
A.2ψ+8π2mh2(EV)ψ=0∇^2\psi+\frac{8\pi^2m}{h^2}(E-V)\psi=0
B.E=hvE=hv
C.Δx.Δph4π\Delta x.\Delta p≥\frac{h}{4\pi}
D.λ=hp\lambda=\frac{h}{p}
Choose the correct answer from the options given below:
A

A-III, B-I, C-IV, D-II

B

A-III, B-I, C-II, D-IV

C

A-III, B-II, C-I, D-IV

D

A-I, B-III, C-II, D-IV

Answer

A-III, B-I, C-II, D-IV

Explanation

Solution

The correct option is(B):A-III, B-I, C-II, D-IV.