Question
Chemistry Question on coordination compounds
| Match List I with List IIList I (Complex) | List II (Hybridization) |
|---|---|
| A. | Ni(CO)4 |
| B. | [Cu(NH3)4]2+ |
| C. | [Fe(NH3)6]2+ |
| D. | [Fe(H2O)6]2+ |
| Choose the correct answer from the options given below: |
A
A-I, B-II, C-III, D-IV
B
A-II, B-I, C-III, D-IV
C
A-I, B-II, C-IV, D-III
D
A-II, B-I, C-IV, D-III
Answer
A-I, B-II, C-IV, D-III
Explanation
Solution
The correct answer is (C) : A-I, B-II, C-IV, D-III
For [Fe(NH3)6]+2,Δ0<P, hence the pairing of electrons does not occur in t2g.
Therefore complex is outer orbital and its hybridisation is sp3d2.