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Question

Chemistry Question on Chemical bonding and molecular structure

Match List-I with List-II : List - IMoleculeList - IIBond enthalpy (kJ mol-1)
(A) HCl(I) 435.8
(B) N2(II) 498
(C) H2(III) 946.0
(D) O2(IV) 431.0
Identify the correct answer from the options given below :
A

A-III, B-IV, C-I, D-II

B

A-IV, B-I, C-III, D-II

C

A-IV, B-III, C-II, D-I

D

A-IV, B-III, C-I, D-II

Answer

A-IV, B-III, C-I, D-II

Explanation

Solution

Bond enthalpy is the energy required to break one mole of a particular bond in a gaseous substance.
A. HCl: The H-Cl bond enthalpy is approximately 431 kJ mol1^{-1} (slightly lower than HBr and higher than HF due to periodic trends down the halogen group). Thus, A-IV.
B. N2_2: The N≡N triple bond is very strong, with a bond enthalpy of approximately 946 kJ mol1^{-1}. Thus, B-III.
C. H2_2: The H-H single bond has a bond enthalpy of approximately 436 kJ mol1^{-1}. Thus, C-I.
D. O2_2: The O=O double bond has a bond enthalpy of approximately 498 kJ mol1^{-1}. Thus, D-II.
Therefore, the correct matching isA-IV, B-III, C-I, D-II.