Question
Chemistry Question on Chemical bonding and molecular structure
Match List-I with List-II : List - IMolecule | List - IIBond enthalpy (kJ mol-1) |
---|---|
(A) HCl | (I) 435.8 |
(B) N2 | (II) 498 |
(C) H2 | (III) 946.0 |
(D) O2 | (IV) 431.0 |
Identify the correct answer from the options given below : |
A
A-III, B-IV, C-I, D-II
B
A-IV, B-I, C-III, D-II
C
A-IV, B-III, C-II, D-I
D
A-IV, B-III, C-I, D-II
Answer
A-IV, B-III, C-I, D-II
Explanation
Solution
Bond enthalpy is the energy required to break one mole of a particular bond in a gaseous substance.
A. HCl: The H-Cl bond enthalpy is approximately 431 kJ mol−1 (slightly lower than HBr and higher than HF due to periodic trends down the halogen group). Thus, A-IV.
B. N2: The N≡N triple bond is very strong, with a bond enthalpy of approximately 946 kJ mol−1. Thus, B-III.
C. H2: The H-H single bond has a bond enthalpy of approximately 436 kJ mol−1. Thus, C-I.
D. O2: The O=O double bond has a bond enthalpy of approximately 498 kJ mol−1. Thus, D-II.
Therefore, the correct matching isA-IV, B-III, C-I, D-II.