Question
Chemistry Question on Aromatic Hydrocarbon
| Match List I with List IIList-I | Reaction | List-II | Reagents |
|---|---|---|---|
| (A) | Hoffmann Degradation | (I) | Conc.KOH |
| (B) | Clemenson reduction | (II) | CHC, NaOH/H O 3 3 |
| (C) | Cannizaro reaction | (III) | Br2, NaOH |
| (D) | Reimer-Tiemann Reaction | (IV) | Zn-Hg/HCl |
| Choose the correct answer from the option given below: |
A
(A)-III, (B) -IV, (C) – II, (D)-I
B
(A)-III, (B) -IV, (C) –I, (D)-II
C
(A)-II, (B) -IV, (C) –I, (D)-III
D
(A)-II, (B) -I, (C) – III, (D)-IV
Answer
(A)-III, (B) -IV, (C) –I, (D)-II
Explanation
Solution
Reaction Reagents (A) Hoffmann degradation 🡢Br2, NaOH (B) Clemenson reduction 🡢 Zn-Hg/HCl (C) Cannizaro-reaction 🡢 Conc. KOH, (D) Reimer-Tiemann reaction 🡢 CHCl3, NaOH/H3O+
Therefore Correct match is : (A)-III, (B) -IV, (C) -I, (D)-II