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Question

Mathematics Question on Differential Equations

Match List I with List II

List IList II
A. [1+(dydx)2]=d2ydx2A.\ [1 + (\frac{dy}{dx})^2] = \frac{d^2y}{dx^2}I. order 2, degree 3
B. (d3ydx2)23d2ydx2+2(dydx)4=y4B. \ (\frac{d^3y}{dx^2})^2 - 3\frac{d^2y}{dx^2} + 2(\frac{dy}{dx})^4 = y^4II. order 2, degree 1
C. (dydx)2+(d2ydx2)3=0C. \ (\frac{dy}{dx})^2 + (\frac{d^2y}{dx^2})^3 = 0III. order 1, degree 2
D. (dydx)2+6y3=0D.\ (\frac{dy}{dx})^2 + 6y^3 = 0IV. order 3, degree 2

Choose the correct answer from the options given below:

A

А-І, В-II, C-IV, D-II

B

А-III, В-I, C-II, D-IV

C

A-IV, B-II, C-III, D-I

D

A-II, B-IV, C-I, D-III

Answer

A-II, B-IV, C-I, D-III

Explanation

Solution

The correct option is (D): A-II, B-IV, C-I, D-III