Question

Match List I with List II

| LIST I| | LIST II
---|---|---|---
A.| The minimum value of $f(x)=8x²-4x+7$ is| I.| 48
B.| The maximum value of $f(x) = x+\frac{1}{x}, x < 0$ is| II.| 13
C.| The maximum slope of the cure $y = -2x^3+6x^2+7x+26$ is| III.| -2
D.| The minimum value of $f(x) = x² +\frac{128}{x}$ is| IV.| $\frac{13}{2}$

Choose the correct answer from the options given below:

• A. (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
• B. (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
• C. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
• D. (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Answer 1

Answer: (B)

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Answer 2

The correct option is (B):(A)-(IV), (B)-(III), (C)-(II), (D)-(I)