Question

Match List-I with List-II:List-I ( Ions )	List-II ( No. of unpaired electrons )
A	Zn$^{2+}$
B	Cu$^{2+}$
C	Ni$^{2+}$
D	Fe$^{2+}$
Choose the correct answer from the options given below:

• A. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
• B. (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
• C. (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
• D. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Answer 1

Answer: (C)

(A)-(I), (B)-(III), (C)-(IV), (D)-(II)

Answer 2

1. Zn$^{2+}$: Electron configuration of Zn is [Ar] 3d$^{10}$. The ion has 0 unpaired electrons. Therefore, (A) - (I).\\\2. Cu$^{2+}$: Electron configuration of Cu is [Ar] 3d$^{10}$ 4s$^1$. The ion has 1 unpaired electron after losing 2 electrons. Therefore, (B) - (III).\\\3. Ni$^{2+}$: Electron configuration of Ni is [Ar] 3d$^8$ 4s$^2$. The ion has 2 unpaired electrons. Therefore, (C) - (IV).\\\4. Fe$^{2+}$: Electron configuration of Fe is [Ar] 3d$^6$ 4s$^2$. The ion has 4 unpaired electrons. Therefore, (D) - (II).\\\Thus, the correct matches are: (A) - (I), (B) - (III), (C) - (IV), (D) - (II).