Question
Chemistry Question on Alcohols, Phenols and Ethers
| Match List-I with List-II:List-I Compound | List-II Product in Basic Medium (in NaOH + Heat) |
|---|---|
| A | Ethanal |
| B | Methanal |
| C | Benzenecarbaldehyde |
| D | Acetone |
| Choose the correct answer from the options given below: |
A
A-I, B-II, C-III, D-IV
B
A-II, B-IV, C-I, D-III
C
A-I, B-II, C-IV, D-III
D
A-III, B-IV, C-I, D-II
Answer
A-I, B-II, C-IV, D-III
Explanation
Solution
Aldehydes and ketones undergo different reactions in basic medium: Ethanal undergoes aldol condensation to give 3-Hydroxybutanal and But-2-enal. Methanal reacts to form formic acid and methanol. Benzenecarbaldehyde forms benzoic acid and phenylmethanol. Acetone undergoes a reaction to give 4-Hydroxy-4-methylpentan-2-one and 4-Methylpent-3-en-2-one.