Question
Chemistry Question on Gas laws
Match List I with List II. | List I (Anion) | List II (gas evolved on reaction with dil H2SO4) | |
---|---|---|---|
A. | CO32− | I. | Colourless gas which turns lead acetate paper black. |
B. | S2– | II. | Colourless gas which turns acidified potassium dichromate solution green |
C. | SO32− | III. | Brown fumes which turns acidified KI solution containing starch blue. |
D. | NO2− | IV. | Colourless gas evolved with brisk effervescence, which turns lime water milky. |
Choose the correct answer from the options given below: |
A
A-III, B-I, C-II, D-IV
B
A-II, B-I, C-IV, D-III
C
A-IV, B-I, C-III, D-II
D
A-IV, B-I, C-II, D-III
Answer
A-IV, B-I, C-II, D-III
Explanation
Solution
CO32−: On action of diluted sulphuric acid, CO2 gas is released which turns lime water milky.
S2−: On action of diluted sulphuric acid, H2S gas is released which turns lead acetate paper black.
SO32−: On action of diluted H2SO4,SO2 gas is evolved which turns acidified potassium dichromate solution green.
NO2−: On action of dil H2SO4,NO2 gas is evolved which turns Kl solution contain starch blue.
Hence, the correct option is (D): A−IV,B−I,C−II,D−III