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Chemistry Question on Gas laws

Match List I with List II.List I (Anion)List II (gas evolved on reaction with dil H2SO4H_2SO_4)
A.CO32CO_3^{ 2−}I.Colourless gas which turns lead acetate paper black.
B.S2S^{2–}II.Colourless gas which turns acidified potassium dichromate solution green
C.SO32SO_3^{ 2−}III.Brown fumes which turns acidified KI solution containing starch blue.
D.NO2NO_2^{−}IV.Colourless gas evolved with brisk effervescence, which turns lime water milky.
Choose the correct answer from the options given below:
A

A-III, B-I, C-II, D-IV

B

A-II, B-I, C-IV, D-III

C

A-IV, B-I, C-III, D-II

D

A-IV, B-I, C-II, D-III

Answer

A-IV, B-I, C-II, D-III

Explanation

Solution

CO32CO_3^{ 2−}: On action of diluted sulphuric acid, CO2CO_2 gas is released which turns lime water milky.

S2:S ^{2-}: On action of diluted sulphuric acid, H2SH_2S gas is released which turns lead acetate paper black.

SO32SO_3^{ 2−}: On action of diluted H2SO4,SO2 H_2SO_4, SO_2 gas is evolved which turns acidified potassium dichromate solution green.

NO2NO^{2−}: On action of dil H2SO4,NO2H_2SO_4, NO_2 gas is evolved which turns Kl solution contain starch blue.

Hence,Hence, the correct option is (D): AIV,BI,CII,DIIIA-IV, B-I, C-II, D-III