Question
Chemistry Question on Periodic properties
Match List - I with List - II.Choose the correct answer from the options given below.
(A)-(IV), (B), (II), (C)-(I), (D)-(III)
(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Solution
(A) Phenol, Zn/Δ: When phenol is treated with zinc dust and heated, it gets reduced to benzene. Thus, (A) corresponds to (III) Benzene.
(B) Phenol, CHCl3, NaOH, HCl (Reimer-Tiemann Reaction): Phenol undergoes the Reimer-Tiemann reaction with chloroform and aqueous sodium hydroxide, forming salicylaldehyde. Thus, (B) corresponds to (I) Salicylaldehyde.
(C) Phenol, CO2, NaOH, HCl (Kolbe-Schmitt Reaction): Phenol reacts with carbon dioxide under high pressure in the presence of sodium hydroxide, followed by acidification, to form salicylic acid. Thus, (C) corresponds to (II) Salicylic acid.
(D) Phenol, Conc. HNO3: Phenol reacts with concentrated nitric acid to form picric acid (2,4,6-trinitrophenol). Thus, (D) corresponds to (IV) Picric acid.
Conclusion: The correct matching is (A)-(III), (B)-(I), (C)-(II), (D)-(IV).